just the exact real root please: (x^6 −1)(x^4 +3x^2 −3)+2x(3x^4 −1)=0


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Question Number 202964 by ajfour last updated on 06/Jan/24

$j u s t t h e e x a c t r e a l r o o t p l e a s e :$ $(x^{6} - 1) (x^{4} + 3 x^{2} - 3) + 2 x (3 x^{4} - 1) = 0$
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