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Question Number 203062 by ajfour last updated on 09/Jan/24

Answered by ajfour last updated on 09/Jan/24

tan θ=((R−(1−R))/(x−c))=(1/x) & x^2 =R^2 −(1−R)^2 =2R−1 ⇒ ((x−c)/x)=((2R−1)/1)=x^2 ((2x−c)/c)=(R/(1−R)) 4x^2 =c^2 (1+(R/(1−R)))^2 =4(2R−1) (2R−1)(2R−2)^2 =c^2 t^2 (t+1)=c^2

tanθ=R−(1−R)x−c=1x&x2=R2−(1−R)2=2R−1⇒x−cx=2R−11=x22x−cc=R1−R4x2=c2(1+R1−R)2=4(2R−1)(2R−1)(2R−2)2=c2t2(t+1)=c2

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