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Question Number 203169 by hardmath last updated on 11/Jan/24

$$\mathrm{If}\mathrm{y}=\tan$$$$\mathrm{Find}{\mathrm{y}}^{{}^{\prime }}=?$$

Answered by a.lgnaoui last updated on 11/Jan/24

$${\mathrm{y}}^{\prime }=\frac{{\cos }^2+\sin {}^2}{\cos {}^2}=\frac{1}{\cos {}^2}=1+\tan {}^2$$$$\mathrm{donc}{\mathrm{y}}^{\prime }=1+{\mathrm{y}}^2$$

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