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Question Number 203211 by ajfour last updated on 12/Jan/24

Answered by MM42 last updated on 12/Jan/24

$$p^2=2-2cosa$$$$q^2=2-2sina$$$$\Rightarrow {(p^2-2)}^2+{(q^2-2)}^2=4✓$$$$$$

Commented by ajfour last updated on 12/Jan/24

$$Ilikeit.precise!$$

Commented by BaliramKumar last updated on 12/Jan/24

$$p^2\le 2\mathrm{\&}{q}^2\le 2$$

Commented by MM42 last updated on 12/Jan/24

$$\underset{―}{\underbrace{⋚}}$$

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