Question and Answers Forum

All Questions      Topic List

UNKNOWN Questions

Previous in All Question      Next in All Question      

Previous in UNKNOWN      Next in UNKNOWN      

Question Number 20326 by kkr1729 last updated on 25/Aug/17

The number of positive inegral  solutions of   abc = 30 is

$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{inegral} \\ $$$$\mathrm{solutions}\:\mathrm{of}\:\:\:{abc}\:=\:\mathrm{30}\:\mathrm{is} \\ $$

Commented by Tinkutara last updated on 25/Aug/17

30 = 2 × 3 × 5 = 8 factors  Required number of ways =^8 C_3  = 56  Ordered triplets =^8 P_3  = 336

$$\mathrm{30}\:=\:\mathrm{2}\:×\:\mathrm{3}\:×\:\mathrm{5}\:=\:\mathrm{8}\:\mathrm{factors} \\ $$$$\mathrm{Required}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:=\:^{\mathrm{8}} {C}_{\mathrm{3}} \:=\:\mathrm{56} \\ $$$$\mathrm{Ordered}\:\mathrm{triplets}\:=\:^{\mathrm{8}} {P}_{\mathrm{3}} \:=\:\mathrm{336} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com