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Question Number 203305 by Ari last updated on 15/Jan/24

Answered by mr W last updated on 15/Jan/24

$$y=mx+c$$$$\Rightarrow x=\frac{y}{m}-\frac{c}{m}\Rightarrow f^{-1}\left(x\right)=\frac{x}{m}-\frac{c}{m}$$$$f^{-1}\left(x\right)=f\left(x\right)$$$$\Rightarrow m=\frac{1}{m}\Rightarrow m=\pm 1$$$$\Rightarrow c=-\frac{c}{m}\Rightarrow c=0orc=any,m=-1$$$$\Rightarrow f\left(x\right)=xorf\left(x\right)=-x+c$$

Commented by Ari last updated on 15/Jan/24

$$thanksMr!$$

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