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Question Number 203351 by Mingma last updated on 17/Jan/24
Answered by witcher3 last updated on 17/Jan/24
x∈E∩F⇔(x∈E&x∈F)⇔(x∈N&1⩽x⩽15&x+12∈Z)x∈N⇒x⩾0⇒x+12∈Z⇒x+12⩾1⇔{x∈N;1⩽x⩽15,x+1∣2},x={1,3,5,7,9,11,13,15}
Commented by Mingma last updated on 17/Jan/24
Perfect ��
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