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Question Number 203351 by Mingma last updated on 17/Jan/24

Answered by witcher3 last updated on 17/Jan/24

x∈E∩F⇔(x∈E &x∈F)  ⇔(x∈N &1≤x≤15&((x+1)/2)∈Z)  x∈N⇒x≥0 ⇒((x+1)/2)∈Z⇒((x+1)/2)≥1  ⇔{x∈N;1≤x≤15, x+1∣2},x={1,3,5,7,9,11,13,15}

xEF(xE&xF)(xN&1x15&x+12Z)xNx0x+12Zx+121{xN;1x15,x+12},x={1,3,5,7,9,11,13,15}

Commented by Mingma last updated on 17/Jan/24

Perfect ��

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