To paint the side of a building, painter normally hoists himself up by pulling on the rope A as in figure. The painter and platform together weigh 200 N. The rope B can withstand 300 N. Find the maximum acceleration of the painter.


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Question Number 20346 by Tinkutara last updated on 25/Aug/17

$To paint the side of a building, painter$ $normally hoists himself up by pulling on$ $the rope A as in figure . The painter and$ $platform together weigh 200 N . The$ $rope B can withstand 300 N . Find the$ $maximum acceleration of the painter .$
Commented by Tinkutara last updated on 25/Aug/17

Commented by ajfour last updated on 25/Aug/17

$l e t m a s s o f p a i n t e r = M$ $m a s s o f p l a t f o r m = m$ $t e n s i o n i n r o p e A = T = \frac{1}{2} T_{B}$ $T = T_{A} = 150 N$ $2 T - (M + m) g = (M + m) a$ $a_{m a x} = \frac{2 T}{(M + m)} - g$ $= \frac{300}{(200 / g)} - g = \frac{g}{2} .$
Commented by Tinkutara last updated on 25/Aug/17

$Thank you very much Sir!$
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