x^4 +cx+d=0 then find p from p^6 −4((d^( 3) /c^4 ))^(1/3) p^2 −1=0 x=(c^(1/3) /2)(p±(√(−p^2 −(8/p))) )


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 203497 by ajfour last updated on 20/Jan/24

$x^{4} + c x + d = 0$ $t h e n f i n d p f r o m$ $p^{6} - 4 {(\frac{d^{3}}{c^{4}})}^{1 / 3} p^{2} - 1 = 0$ $x = \frac{c^{1 / 3}}{2} (p \pm \sqrt{- p^{2} - \frac{8}{p}})$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum