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Question Number 203613 by mr W last updated on 23/Jan/24

Commented by mr W last updated on 23/Jan/24

$$find\frac{R}{r}=?$$

Commented by esmaeil last updated on 23/Jan/24

$$4$$

Answered by mr W last updated on 23/Jan/24

Commented by mr W last updated on 23/Jan/24

$${\left(2R\right)}^2-{(R+2r)}^2={(R+r)}^2-r^2$$$$R^2-3Rr-2r^2=0$$$$\frac{R}{r}=\frac{3+\sqrt{17}}{2}\approx 3.562$$

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