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Question Number 203833 by depressiveshrek last updated on 29/Jan/24

$$\mathrm{How}\mathrm{many}\mathrm{bit}\mathrm{strings}\mathrm{of}\mathrm{length}11\mathrm{have}$$$$\mathrm{exactly}\mathrm{three}\mathrm{consecutive}1\mathrm{s}?$$

Answered by nikif99 last updated on 30/Jan/24

$$Suchatypicalbitstringoflength=11is$$$$000\underset{pos=4}{\underbrace{111}00000}$$$$Casesofpositioning{}^{\prime }{111}^{\prime }are9$$$$startingatpositions1-9.$$

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