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Question Number 203975 by witcher3 last updated on 03/Feb/24

$$\mathrm{Let}\mathrm{P}\in \mathbb{C}\left[\mathrm{X}\right]$$$$\mathrm{p}({\mathrm{x}}^2+1)={\mathrm{p}}^2\left(\mathrm{x}\right)+1$$$$\mathrm{p}\left(0\right)=0$$$$\mathrm{determin}\mathrm{all}\mathrm{polynom}$$

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