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Question Number 204038 by hardmath last updated on 04/Feb/24

$$\mathrm{y}=({\mathrm{x}}^3+1)\cdot 3^{\mathbf{x}}$$$$\Rightarrow {\mathrm{y}}^{{}^{\prime }}=?$$

Answered by deleteduser1 last updated on 04/Feb/24

$$y^{{}^{\prime }}=3^{x+1}\left(x^2\right)+(x^3+1)3^{x}In\left(3\right)$$

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