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Question Number 204072 by Red1ight last updated on 05/Feb/24

((sin^2  θ)/2)=sin 2θ? (90°>θ>0°)

sin2θ2=sin2θ?(90°>θ>0°)

Answered by deleteduser1 last updated on 05/Feb/24

sin^2 θ=4sinθcosθ⇒tanθ=4⇒θ=tan^(−1) (4)≈75.96°

sin2θ=4sinθcosθtanθ=4θ=tan1(4)75.96°

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