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Question Number 204072 by Red1ight last updated on 05/Feb/24
sin2θ2=sin2θ?(90°>θ>0°)
Answered by deleteduser1 last updated on 05/Feb/24
sin2θ=4sinθcosθ⇒tanθ=4⇒θ=tan−1(4)≈75.96°
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