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Question Number 204117 by mokys last updated on 06/Feb/24

solve for θ in terms of y when y = e^θ (cosθ+sinθ)

solveforθintermsofywheny=eθ(cosθ+sinθ)

Commented by mr W last updated on 06/Feb/24

impossible!

impossible!

Commented by mokys last updated on 06/Feb/24

thank you alot sir

thankyoualotsir

Commented by mokys last updated on 06/Feb/24

sory sir i want θ for y

sorysiriwantθfory

Commented by Frix last updated on 07/Feb/24

Maybe y=e^θ (cos θ +i sin θ), because then  it′s possible:  e^(iθ) =cos θ +i sin θ =e^(iθ)   ⇒  y=e^((1+i)θ)   θ=((ln y)/2)+nπ−(((ln y)/2)−nπ)i

Maybey=eθ(cosθ+isinθ),becausethenitspossible:eiθ=cosθ+isinθ=eiθy=e(1+i)θθ=lny2+nπ(lny2nπ)i

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