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Question Number 204171 by cherokeesay last updated on 07/Feb/24

Commented by deleteduser1 last updated on 07/Feb/24

$A r e t h o s e p o i n t s o n t h e c i r c l e t h e v e r t i c e s o f a$ $r e g u l a r h e x a g o n ? I s H t h e m i d p o i n t o f Γ a n d A ?$
	Answered by deleteduser1 last updated on 07/Feb/24

	$I f c o m m e n t a b o v e i s t r u e, t h e n Z A = 4,$ $Γ A^{2} = 4^{2} + 4^{2} - 2 \times 4^{2} c o s 120 = 3 \times 4^{2} \Rightarrow Γ A = 4 \sqrt{3}$ $\Rightarrow H A = 2 \sqrt{3} \Rightarrow [H A Z] = \frac{1}{2} \times 2 \sqrt{3} \times 4 = 4 \sqrt{3}$
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