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Question Number 204236 by Panav last updated on 09/Feb/24

$$\mathit{H}\mathit{e}\mathit{l}\mathit{p}\mathit{f}\mathit{u}\mathit{l}\mathit{q}\mathit{u}\mathit{e}\mathit{s}\mathit{t}\mathit{i}\mathit{o}\mathit{n}\mathit{f}\mathit{o}\mathit{r}\mathit{O}\mathit{l}\mathit{y}\mathit{m}\mathit{p}\mathit{i}\mathit{a}\mathit{d}\mathit{s},\mathit{F}\mathit{i}\mathit{n}\mathit{d}{\mathit{S}\mathit{o}\mathit{l}}^{\mathit{n}}.$$

Commented by Panav last updated on 09/Feb/24

Answered by JDamian last updated on 10/Feb/24

$$R=14\mathrm{cm}$$$$2\times S_{triangle}=R^2{\cos }^{2}45°=\frac{R^2}{2}=98{\mathrm{cm}}^2$$$$S_{fullcircle}=\pi R^2=196\pi {\mathrm{cm}}^2$$$$$$$$S=196\pi -98{\mathrm{cm}}^2$$$$196\pi -98\notin \mathbb{N}$$

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