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Question Number 204293 by depressiveshrek last updated on 11/Feb/24

Prove the following trig identity:  ((2sinα+sin3α+sin5α)/(cosα−2cos2α+cos3α))=((2cos2α)/(tan(α/2)))

Provethefollowingtrigidentity:2sinα+sin3α+sin5αcosα2cos2α+cos3α=2cos2αtanα2

Commented by Frix last updated on 11/Feb/24

Try.  α=(π/6) ⇒ lhs=−5(2+(√3))     rhs=2+(√3)  α=(π/2) ⇒ lhs=1     rhs=−2  ...

Try.α=π6lhs=5(2+3)rhs=2+3α=π2lhs=1rhs=2...

Answered by Frix last updated on 11/Feb/24

It′s false.

Itsfalse.

Commented by depressiveshrek last updated on 11/Feb/24

Why?

Why?

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