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Question Number 204313 by serenity last updated on 12/Feb/24

$$lim\frac{3{\times }^2-8\times -16}{2{\times }^{2}9\times +4}$$$$$$

Answered by Faetmaaa last updated on 27/Feb/24

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{3x^2-8x-16}{2x^2+9x+4}$$$$=\underset{x\to \mathrm{\infty }}{\lim }\frac{3-\frac{8}{x}-\frac{16}{x^2}}{2+\frac{9}{x}+\frac{4}{x^2}}$$$$=\frac{3-0-0}{2+0+0}$$$$=\frac{3}{2}$$

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