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Question Number 204521 by explorerapollo last updated on 20/Feb/24

Commented by TonyCWX08 last updated on 20/Feb/24

I don′t understand your request here.

Idon′tunderstandyourrequesthere.

Answered by mr W last updated on 20/Feb/24

Commented by mr W last updated on 20/Feb/24

2C=(a−((2B)/b))(b−((2A)/a))=ab−2A−2B+((4AB)/(ab)) ab^2 −2(A+B+C)ab+4AB=0 ⇒ab=A+B+C+(√((A+B+C)^2 −4AB)) X=ab−A−B−C=(√((A+B+C)^2 −4AB)) with A=6, B=2, C=5 ⇒X=(√((6+2+5)^2 −4×6×2))=11

2C=(a−2Bb)(b−2Aa)=ab−2A−2B+4ABabab2−2(A+B+C)ab+4AB=0⇒ab=A+B+C+(A+B+C)2−4ABX=ab−A−B−C=(A+B+C)2−4ABwithA=6,B=2,C=5⇒X=(6+2+5)2−4×6×2=11

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