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Question Number 205070 by dimentri last updated on 07/Mar/24

$$\mathrm{Given}\{\begin{array}{l}\mathrm{A}\cap \mathrm{B}=\{\mathrm{a},\mathrm{b}\}\\ \mathrm{A}\cap \mathrm{C}=\{\mathrm{b},\mathrm{c}\}\\ \mathrm{B}\cap \mathrm{C}=\{\mathrm{b},\mathrm{d}\}\end{array}$$$$\mathrm{then}(\mathrm{A}\cap \mathrm{C})+(\mathrm{A}\cap \mathrm{B})+(\mathrm{B}\cap \mathrm{C})$$

Commented by JDamian last updated on 07/Mar/24

$$Doyoumean(\mathrm{A}\cap \mathrm{C})\cup (\mathrm{A}\cap \mathrm{B})\cup (\mathrm{B}\cap \mathrm{C})?$$

Commented by cortano12 last updated on 07/Mar/24

$$\mathrm{no}$$

Commented by A5T last updated on 07/Mar/24

$$‘‘{+}^{″}generallyisusedtosumcardinalityofsets.$$$$Areyoureferringtothat?$$

Commented by cortano12 last updated on 07/Mar/24

$$\mathrm{A}+\mathrm{B}=(\mathrm{A}\cup \mathrm{B})-(\mathrm{A}\cap \mathrm{B})$$$$\mathrm{or}\mathrm{A}+\mathrm{B}=(\mathrm{A}-\mathrm{B})\cup (\mathrm{B}-\mathrm{A})$$

Commented by A5T last updated on 07/Mar/24

$$ThenD=(A\cap C)+(A\cap B)=\{a,c\}$$$$D+(B\cap C)=(A\cap C)+(A\cap B)+(B\cap C)=\{a,b,c,d\}$$

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