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Question Number 205083 by BaliramKumar last updated on 07/Mar/24

Answered by A5T last updated on 07/Mar/24

1×1×30;1×2×15;1×3×10;1×5×6; 2×3×5; There are 5 ways upto permutation but if order matters there are, 4×3!+((3!)/(2!))=27

1×1×30;1×2×15;1×3×10;1×5×6;2×3×5;Thereare5waysuptopermutationbutifordermattersthereare,4×3!+3!2!=27

Commented by BaliramKumar last updated on 07/Mar/24

thanks sir

thankssir

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