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Question Number 205117 by BaliramKumar last updated on 09/Mar/24

Answered by Rasheed.Sindhi last updated on 09/Mar/24

(x/y)+(y/x)=2  ⇒x^2 +y^2 =2xy  ⇒x^2 −2xy+y^2 =0  ⇒(x−y)^2 =0  ⇒x−y=0  ⇒x=y  ⇏ x≠y  (a) Zero

xy+yx=2x2+y2=2xyx22xy+y2=0(xy)2=0xy=0x=yxy(a)Zero

Commented by BaliramKumar last updated on 09/Mar/24

thanks

thanks

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