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Question Number 205172 by shunmisaki007 last updated on 12/Mar/24
x(t)=c+tx′(t)∣cisconstant.(1)Findx(t).(2)Findx(t)whenx(0)=x0.
Commented by lepuissantcedricjunior last updated on 12/Mar/24
x(t)=c+tx′(t)c∈Ronatx′(t)−x(t)=−cxk=e∫1tdt=kelnt=ktfaisonsvarierlaconstancek(t)x(t)=k(t)tx′(t)=k′(t)t+k(t)tx′(t)−x(t)=−ct2k′(t)+k(t)t−k(t)t=−ck′(t)=−ct2=>k(t)=ct+moum∈Rxm(t)=mt+cx(o)=x0=>xm(0)=m(0)+c=x0=>c=x0xm(t)=mt+x0oum∈Rxm(t)=mt+x0oum∈R.............lepuissantDr......................
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