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Question Number 205321 by gopikrishnan last updated on 16/Mar/24

a^→ =i^� +3j^� +4k^�  b^→ =2i^� −3j^� +4k^�  c^→ =5i^� −2j^� +4k^�  given that p^→ ×b^→ =b^→ ×c^→  and p^→ .b^→ =0 then the value of p^→ (i^� −j^� +k^� )is

a=i^+3j^+4k^b=2i^3j^+4k^c=5i^2j^+4k^giventhatp×b=b×candp.b=0thenthevalueofp(i^j^+k^)is

Answered by gopikrishnan last updated on 18/Mar/24

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