Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 20558 by khamizan833@gmail.com last updated on 28/Aug/17

Commented by ajfour last updated on 28/Aug/17

full form of cot x is cotangent x.

$${full}\:{form}\:{of}\:\mathrm{cot}\:{x}\:{is}\:{cotangent}\:{x}. \\ $$

Answered by Tinkutara last updated on 28/Aug/17

(1−cot 22°)(1−cot 23°)=1−cot 23°− cot 22°+cot 22°cot 23° cot 45°=((cot 22°cot 23°−1)/(cot 22°+cot 23°))=1 ⇒cot 22°cot 23°−cot 22°−cot 23°=1 ∴(1−cot 22°)(1−cot 23°)=2

$$\left(\mathrm{1}−\mathrm{cot}\:\mathrm{22}°\right)\left(\mathrm{1}−\mathrm{cot}\:\mathrm{23}°\right)=\mathrm{1}−\mathrm{cot}\:\mathrm{23}°− \\ $$$$\mathrm{cot}\:\mathrm{22}°+\mathrm{cot}\:\mathrm{22}°\mathrm{cot}\:\mathrm{23}° \\ $$$$\mathrm{cot}\:\mathrm{45}°=\frac{\mathrm{cot}\:\mathrm{22}°\mathrm{cot}\:\mathrm{23}°−\mathrm{1}}{\mathrm{cot}\:\mathrm{22}°+\mathrm{cot}\:\mathrm{23}°}=\mathrm{1} \\ $$$$\Rightarrow\mathrm{cot}\:\mathrm{22}°\mathrm{cot}\:\mathrm{23}°−\mathrm{cot}\:\mathrm{22}°−\mathrm{cot}\:\mathrm{23}°=\mathrm{1} \\ $$$$\therefore\left(\mathrm{1}−\mathrm{cot}\:\mathrm{22}°\right)\left(\mathrm{1}−\mathrm{cot}\:\mathrm{23}°\right)=\mathrm{2} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com