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Question Number 205817 by hardmath last updated on 31/Mar/24

$$2^{\mathbf{x}+{\mathbf{log}}_{2}3}=12\Rightarrow \mathrm{find}:\mathrm{x}=?$$

Answered by A5T last updated on 31/Mar/24

$$\left(2^x\right)\left(2^{{log}_{2}3}\right)=12\Rightarrow \left(2^x\right)\left(3\right)=12\Rightarrow 2^x=4\Rightarrow x=2$$

Answered by MM42 last updated on 31/Mar/24

$$2^x\times 3=12\Rightarrow x=2✓$$

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