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Question Number 206020 by NANIGOPAL last updated on 05/Apr/24
Answered by cortano12 last updated on 05/Apr/24
=limx→0x(2tanx1−tan2x−2tanx)4sin4x=limx→02xtanx(1−(1−tan2x))4sin4x=12limx→0tan2xsin2x=12
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