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Question Number 206045 by mr W last updated on 05/Apr/24

Commented by mr W last updated on 05/Apr/24

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Answered by HeferH24 last updated on 05/Apr/24

$$A+E=F+B...(+)$$$$F+D=E+C$$$$(F+E=21)$$$$A+D=B+C$$$$$$$$A+9+x+D=E+F+C+B$$$$9+x=21$$$$x=12$$

Commented by HeferH24 last updated on 05/Apr/24

Commented by mr W last updated on 05/Apr/24

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Answered by A5T last updated on 07/Apr/24

$$9+\left[BGE\right]+x+\left[HFD\right]=21+\left[AGF\right]+\left[EHC\right]..\left(i\right)$$$$9+\left[AGF\right]+x+\left[HEC\right]=21+\left[BGE\right]+\left[HFD\right]..\left(ii\right)$$$$\left(i\right)-\left(ii\right):\left[BGE\right]-\left[AGF\right]+\left[HFD\right]-\left[HEC\right]$$$$=\left[AGF\right]-\left[BGE\right]+\left[EHC\right]-\left[HFD\right]$$$$\Rightarrow \left[BGE\right]+\left[HFD\right]=\left[AGF\right]+\left[HEC\right]into\left(i\right)$$$$\Rightarrow 9+x=21\Rightarrow x=12$$

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