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Question Number 206048 by MATHEMATICSAM last updated on 05/Apr/24

$$\mathrm{Prove}\mathrm{that}{2}^{{\sin }^2\theta }+2^{{\cos }^2\theta }⩾2\sqrt{2}.$$

Answered by A5T last updated on 05/Apr/24

$$2^{{sin}^2\theta }+2^{{coz}^2\theta }⩾2\sqrt{2^{{sin}^2\theta +{cos}^2\theta }}=2\sqrt{2}$$

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