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Question Number 206198 by lmcp1203 last updated on 09/Apr/24

Answered by A5T last updated on 09/Apr/24

$$\frac{sin4\theta }{AD}=\frac{sin(90-3\theta )}{AB};\frac{sin\left(\theta \right)}{AD}=\frac{sin(90-4\theta )}{CD=AB}$$$$\Rightarrow \frac{sin\left(4\theta \right)}{sin(90-3\theta )}=\frac{sin\left(\theta \right)}{sin(90-4\theta )}\Rightarrow x=20°$$

Answered by lmcp1203 last updated on 09/Apr/24

$$thanks.$$

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