Expand x^2 + 2x + 3 respect to x = −2. (a) (x − 2)^2 −2(x + 2) + 3 (b) (x + 2)^2 −2(x + 2) + 3 (c) (x + 2)^2 + 2(x + 2) + 3 (d) (x − 2)^2 −2(x − 2) − 3 is it taylors theorem?


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Question Number 206230 by BaliramKumar last updated on 09/Apr/24

$Expand x^{2} + 2 x + 3 r e s p e c t t o x = - 2 .$ $(a) {(x - 2)}^{2} - 2 (x + 2) + 3$ $(b) {(x + 2)}^{2} - 2 (x + 2) + 3$ $(c) {(x + 2)}^{2} + 2 (x + 2) + 3$ $(d) {(x - 2)}^{2} - 2 (x - 2) - 3$ $is it taylors theorem ?$
	Answered by Frix last updated on 10/Apr/24

	$x^{2} + 2 x + 3$ $x = t - 2$ $t^{2} - 2 t + 3$ $t = x + 2$ ${(x + 2)}^{2} - 2 (x + 2) + 3$
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