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Question Number 206302 by ayietaamos last updated on 11/Apr/24
Answered by A5T last updated on 11/Apr/24
k=ln(T3y)−12
Answered by MATHEMATICSAM last updated on 11/Apr/24
T=3ye2k+1⇒e2k+1=T3y⇒2k+1=ln(T3y)⇒2k=ln(T3y)−1⇒2k=ln(T3y)−lne⇒2k=ln(T3ye)⇒k=12ln(T3ye)
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