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Question Number 206353 by BaliramKumar last updated on 12/Apr/24

Commented by Rasheed.Sindhi last updated on 15/Apr/24

$I t h i n k 15 i s w r o n g h e r e, i t s h o u l d$ $b e 14 o r o t h e r w i s e t h e a n s w e r i s$ $n o t c o r r e c t .$
Commented by Rasheed.Sindhi last updated on 15/Apr/24

$PLEASE response .$
Commented by BaliramKumar last updated on 15/Apr/24

$This is solution$ $i am no under stand$
Commented by BaliramKumar last updated on 15/Apr/24

Commented by Rasheed.Sindhi last updated on 15/Apr/24

$∙ V e r y p o o r^{'} p h y s i c a l {h e a l t h}^{'} o f$ $t h e s o l u t i o n! I^{'} l l t r y i t s b e t t e r$ $v e r s i o n b e l o w .$ $∙ {C o u d n}^{'} t s a y a b o u t^{'} m e n t a l {h e a l t h}^{'}$ $i - e^{'} l o g i c a l {f i t n e s s}^{'} o f t h e s o l u t i o n .$ $(T h e r e a r e m a n y e x e r t s f o r t h i s)$ $a l b e i t I^{'} l l g i v e m y o w n u n d e r s t a n d i n g$ $a b o u t t h e q u e s t i o n, a l t h o u g h a f t e r$ $r e p o s t i n g i t .$
Commented by Rasheed.Sindhi last updated on 15/Apr/24

$14 . (2) N u m b e r o f s o l d i e r s s t a n d i n g$ $i n t h e h o l l o w s q u a r e w i t h d e p t h$ $o f 8, 10, 12 o r 15 = 4 \times l c m (8, 10,$ $12, 15) b e c a u s e t h e y w i l l s t a n d$ $o n t h e p e r i m e t e r o f t h e s q u a r e$ $o n l y . . . l e a s t c o m m o n m u l t i p l e$ $o f 8, 10, 12 a n d 15 :$ $2 \underset{―}{∣ 8, 10, 12, 15}$ $2 \underset{―}{∣ 4, 5, 6, 15}$ $3 \underset{―}{∣ 2, 5, 3, 15}$ $5 \underset{―}{∣ 2, 5, 1, 5}$ $2, 1, 1, 1$ $. . . L S = 2 \times 2 \times 3 \times 5 \times 2 = 120$ $T h e t o t a l n u m b e r r e q u i r e d i n t h e h o l l o w s q u a r e$ $= 4 \times 4 \times 30$ $B u t a t l e a s t t h e n u m b e r o f s o l d i e r s$ $s t a n d i n g i n a s o l i d s q u a r e$ $= 4 \times 4 \times 30 \times 30 = 14400$
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