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Question Number 20640 by oyshi last updated on 30/Aug/17

$$\sin \theta =K\cos (\theta -\alpha )$$$$soproofit,\cot \theta =\frac{1-K\sin \alpha }{K\cos \alpha }$$

Answered by mrW1 last updated on 30/Aug/17

$$\sin \theta =\mathrm{K}(\cos \theta \cos \alpha +\sin \theta \sin \alpha )$$$$(1-\mathrm{Ksin}\alpha )\sin \theta =\mathrm{Kcos}\alpha \cos \theta$$$$\Rightarrow \cot \theta =\frac{\cos \theta }{\sin \theta }=\frac{1-\mathrm{Ksin}\alpha }{\mathrm{Kcos}\alpha }$$

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