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Question Number 206430 by cortano21 last updated on 14/Apr/24

Answered by mr W last updated on 14/Apr/24

AB=a, say  7^2 =a^2 +8^2 −2×8a cos 60°  a^2 −8a +15=0  (a−3)(a−5)=0  a= 5 or 3 (rejected, since AD=2a must ≥8)  GD=2a−8=2×5−8=2  ((DH)/a)=((GD)/8) =(2/8)=(1/4)  ⇒DH=(a/4) ⇒x=(3/4)a=((15)/4) ✓

AB=a,say72=a2+822×8acos60°a28a+15=0(a3)(a5)=0a=5or3(rejected,sinceAD=2amust8)GD=2a8=2×58=2DHa=GD8=28=14DH=a4x=34a=154

Answered by A5T last updated on 14/Apr/24

AD=2a⇒DG=2a−8  (7/(GH))=(8/(DG))⇒GH=((7(a−4))/4)  (a/(DH))=(7/(GH))⇒DH=((a(a−4))/4)⇒x=((8a−a^2 )/4)  a^2 +8^2 −a×8=49⇒8a−a^2 =15⇒x=((15)/4)

AD=2aDG=2a87GH=8DGGH=7(a4)4aDH=7GHDH=a(a4)4x=8aa24a2+82a×8=498aa2=15x=154

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