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Question Number 206618 by MATHEMATICSAM last updated on 20/Apr/24

If A = sin^4 θ + cos^4 θ then select the   correct option:  i) 0 < A < (1/2)  ii) 1 < A < (3/2)  iii) (1/2) ≤ A ≤ 1  iv) (3/2) ≤ A ≤ 2

IfA=sin4θ+cos4θthenselectthecorrectoption:i)0<A<12ii)1<A<32iii)12A1iv)32A2

Answered by MM42 last updated on 20/Apr/24

A=(sin^2 θ+cos^2 θ)^2 −2sin^2 θcos^2 θ  =1−(1/2)sin^2 (2θ)⇒ans:  (1/2)≤A≤1   ✓

A=(sin2θ+cos2θ)22sin2θcos2θ=112sin2(2θ)ans:12A1

Answered by Frix last updated on 20/Apr/24

A=(3/4)+((cos 4x)/4)  (1/2)≤A≤1

A=34+cos4x412A1

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