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Question Number 206789 by BaliramKumar last updated on 25/Apr/24

Answered by A5T last updated on 25/Apr/24

((a_1 a_2 ...a_n ))^(1/n) =P ((a_(n+1) a_(n+2) ...a_(3n) ))^(1/(2n)) =Q ⇒((PQ^2 ))^(1/3) =((a_1 a_2 ...a_(3n) ))^(1/(3n)) =P^(1/3) Q^(2/3)

a1a2...ann=Pan+1an+2...a3n2n=Q⇒PQ23=a1a2...a3n3n=P13Q23

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