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Question Number 206912 by BaliramKumar last updated on 30/Apr/24
Answered by A5T last updated on 30/Apr/24
cos2θ+3(1−cos2θ)+2=5−2cos2θ⇒Max=5−0;Min=5−2⇒Difference=2
Answered by mr W last updated on 30/Apr/24
1−sin2θ+3sin2θ+2=3+2sin2θ⩾3=min⩽5=max⇒max−min=2⇒(c)
Answered by MM42 last updated on 30/Apr/24
1+cos2θ2+31−cos2θ2+2=4−cos2θ⇒M=5&m=3⇒M−m=2✓
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