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Question Number 206956 by mr W last updated on 01/May/24

Commented by mr W last updated on 01/May/24

$$findtheradiusofcircle.$$

Answered by Frix last updated on 01/May/24

$$3\mathrm{points}\mathrm{given}$$$$\left(\begin{array}{c}0\\ 0\end{array}\right)\left(\begin{array}{c}0\\ 6\end{array}\right)\left(\begin{array}{c}12\\ 12\end{array}\right)$$$$\Rightarrow \mathrm{Triangle}\mathrm{with}\mathrm{sides}$$$$66\sqrt{5}12\sqrt{2}$$$$\Rightarrow R=3\sqrt{10}$$

Commented by mr W last updated on 01/May/24

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Answered by mr W last updated on 01/May/24

Commented by mr W last updated on 01/May/24

$$BC=\sqrt{{(6+4+2)}^2+{(4+2)}^2}=6\sqrt{5}$$$$R=\frac{BC}{2\sin A}=\frac{6\sqrt{5}}{2\times \frac{\sqrt{2}}{2}}=3\sqrt{10}$$

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