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Question Number 207008 by mr W last updated on 03/May/24

Answered by A5T last updated on 03/May/24

Commented by A5T last updated on 03/May/24

$$\frac{5}{BO}=\frac{6}{CO}\Rightarrow \frac{BO}{CO}=\frac{5}{6};BO=5x;CO=6x$$$$\Rightarrow 11x=7\Rightarrow BO=\frac{35}{11};CO=\frac{42}{11}$$$${(6-x)}^2+r^2=\frac{{42}^2}{{11}^2}...\left(i\right)$$$${(5-x)}^2+r^2=\frac{{35}^2}{{11}^2}...\left(ii\right)$$$$\left(i\right)\mathrm{\&}\left(ii\right)\Rightarrow r=\frac{12\sqrt{6}}{11}\approx 2.6722$$

Commented by mr W last updated on 03/May/24

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Answered by cherokeesay last updated on 03/May/24

Commented by mr W last updated on 03/May/24

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