Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 20705 by mondodotto@gmail.com last updated on 01/Sep/17

Answered by dioph last updated on 01/Sep/17

$$40=\frac{\mathrm{\Sigma }{x}_i-(43+35)+(34+53)}{200}$$$$8000=\mathrm{\Sigma }{x}_i-78+87$$$$\mathrm{\Sigma }{x}_i=7991$$$$m=\frac{\mathrm{\Sigma }{x}_i}{200}=\frac{7991}{200}$$$$m=39.955$$$$15=\sqrt{\frac{[\mathrm{\Sigma }{x}_i^2-({43}^2+{35}^2)+({34}^2+{53}^2)]-\left[{(\mathrm{\Sigma }{x}_i-(43+35)+(34+43))}^2/200\right]}{199}}$$$$225=\frac{[\mathrm{\Sigma }{x}_i^2+891]-\left[{8000}^2/200\right]}{199}$$$$44775=\mathrm{\Sigma }{x}_i^2-319109$$$$\mathrm{\Sigma }{x}_i^2=363884$$$$\sigma =\sqrt{\frac{\mathrm{\Sigma }{x}_i^2-{\left(\mathrm{\Sigma }{x}_i\right)}^2/200}{199}}$$$$\sigma =\sqrt{\frac{363884-{7991}^2/200}{199}}$$$$\sigma \approx 14.971$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com