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Question Number 207179 by efronzo1 last updated on 08/May/24

	Answered by mr W last updated on 08/May/24

	$3 \times 4 \times 3 \times 2 = 72 s u c h n u m b e r s$
	Commented by efronzo1 last updated on 09/May/24

	$\underset{⏟}{B} \underset{⏟}{}$
	Commented by mr W last updated on 09/May/24

	$n o s i r!$ $t o s e l e c t t h e l a s t d i g i t t h e r e a r e 3$ $p o s s i b i l i t i e s (1, 3, 5) . f o r t h e$ $r e m a i n i n g 4 d i g i t s t h e r e a r e 4 \times 3 \times 2 \times 1$ $p o s s i b i l i t i e s . s o t o t a l l y t h e r e a r e$ $3 \times 4 \times 3 \times 2 \times 1 = 72 n u m b e r s i f$ $n o r e p e t i t i o n i s a l l o w e d .$
	Answered by som(math1967) last updated on 08/May/24

	$5^{4} \times 3, i f r e p e t i t i o n i s a l l o w e d$
	Commented by som(math1967) last updated on 09/May/24

	$I f r e p e t i t i o n n o t a l l o w$ $◼ ◼ ◼ ◼ 1 o r 3 o r 5$ $P_{4}^{4} \times 3 = 4! \times 3 = 72$
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