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Question Number 207274 by hardmath last updated on 10/May/24

$${\log }_{\mathbf{abc}}\mathrm{a}=2\mathrm{and}{\log }_{\mathbf{abc}}\mathrm{b}=3$$$$\mathrm{find}:{\log }_{\mathbf{abc}}\mathrm{c}=?$$

Answered by MM42 last updated on 10/May/24

$${log}_{abc}a+{log}_{abc}b+{log}_{abc}c=1$$$$\Rightarrow {log}_{abc}c=-4✓$$

Commented by hardmath last updated on 10/May/24

$$\mathrm{thank}\mathrm{you}\mathrm{dear}\mathrm{professor}$$

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