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Question Number 207352 by NasaSara last updated on 12/May/24

calculate:   ∫_(Π/4) ^(Π/2) ⌊cot(x)⌋ dx

calculate:Π4Π2cot(x)dx

Commented by NasaSara last updated on 12/May/24

thank you

thankyou

Commented by Berbere last updated on 12/May/24

withe Pleasur

withePleasur

Commented by Berbere last updated on 12/May/24

0≤cot(x)<1 ;∀x∈](π/4);(π/2)]⇒[cot(x)]=0  ∫_(π/4) ^(π/2) [cot(x)]dx=0

0cot(x)<1;x]π4;π2][cot(x)]=0π4π2[cot(x)]dx=0

Answered by MM42 last updated on 12/May/24

(π/4)<x<(π/2)⇒0<cotx<1⇒⌊cotx⌋=0  ⇒I=0 ✓

π4<x<π20<cotx<1cotx=0I=0

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