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Question Number 207362 by mr W last updated on 12/May/24
Answered by A5T last updated on 12/May/24
Ptolemy′stheorem:AC×BP=AP×BC+AB×PCAB=AC=BC⇒PB=PA+PC
Answered by sniper237 last updated on 13/May/24
LetQ∈[BP]suchasPQ=PCAsmesBPC=mesBAC=60thenQPCisequilateralasABCSor(A)=Bandr(P)=Qwithr=R(C;π3)Thusrisanisometry,PA=BQThenPB=PQ+QB=PC+PA
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