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Question Number 207426 by mr W last updated on 14/May/24

Answered by A5T last updated on 14/May/24

Commented by A5T last updated on 14/May/24

$$a^2+d^2={2022}^2...\left(i\right)$$$$a^2+c^2={2023}^2...\left(ii\right)$$$$b^2+c^2={2024}^2...\left(iii\right)$$$$\left(iii\right)-\left(ii\right)+\left(i\right):b^2+d^2={2024}^2-{2023}^2+{2022}^2={?}^2$$$$\Rightarrow ?=\sqrt{4092531}$$

Commented by mr W last updated on 14/May/24

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