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Question Number 207458 by 073 last updated on 16/May/24

Commented by 073 last updated on 16/May/24

$$????$$

Commented by mr W last updated on 16/May/24

$$\mathrm{B}(x,y)=\frac{\mathrm{\Gamma }\left(x\right)\mathrm{\Gamma }\left(y\right)}{\mathrm{\Gamma }(x+y)}\stackrel{!}{=}\mathrm{\Gamma }\left(x\right)$$$$\Rightarrow \frac{\mathrm{\Gamma }\left(y\right)}{\mathrm{\Gamma }(x+y)}=1$$$$\Rightarrow \mathrm{\Gamma }(x+y)=\mathrm{\Gamma }\left(y\right)\Rightarrow nosolutionfory$$

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