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Question Number 207462 by hardmath last updated on 16/May/24

$$4\sin \frac{\mathbf{x}}{2}=1\mathrm{find}:\mathbf{x}=?$$

Commented by Frix last updated on 16/May/24

$$x=4n\pi +{2\sin }^{-1}\frac{1}{4}\vee x=2(2n+1)\pi -{2\sin }^{-1}\frac{1}{4}$$

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