Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 207463 by hardmath last updated on 16/May/24

$$1-{\sin }^2\mathrm{x}=\sqrt{2}\mathrm{find}:\mathbf{x}=?$$

Answered by Frix last updated on 16/May/24

$${\cos }^{2}x=\sqrt{2}>1\Rightarrow \mathrm{no}\mathrm{solution}\mathrm{for}x\in \mathbb{R}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com